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`Eunice
`18
`15 sept 88
`Hardcorer
`N'Devils
`OSLE LiJiang
`NTU Archery
Loves....
`cows!!
`archery!
`05A1 / 05S5A / PM
`Jay Chou!
`S.H.E
`Chatting!
`taking photographs!
Wednesday, May 04, 2005
9:33 PM
To prove that Eunice = simple and nice and clever
let Pn be the statement Eunice = nice + simple + clever
let n=1
LHS= 1 Eunice
RHS= nice + simple + clever
Thus, P1 is true.
Assume Pk is true for all positive integers k
k Eunice = k (nice + simple + clever)
To prove Pk+1 is true, i.e (k+1) Eunice = (k+1) simple + (k+1) nice + (k+1)clever
RHS:
(k+1) (simple+nice+clever)
= (k+1)simple + (k+1)nice + (k+1)clever
= LHS
Since Pk is true --> P k+1 is true. P1 is also true. Thus, by Mathematical Inductions, Pn is true for all positive integers k.
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